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Discussion of "ta'u'i"
[parent] [root]
Comment #2: Factoring out seltau
Curtis W Franks (Tue Nov 7 08:27:01 2017)

This word does not factor out seltau (it does not take "ax+ay" and produce
"a(x+y)"). I would like this function somehow (in another word), but I do
not know how to make it happen just yet.

Rather, this word simply takes "ax+by" and sets b=b`ab``, where b` and b``
are any other seltau present in y's construct and which compound with this
word (which represents/pastes in seltau a).

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